What is the approximate maximum number of 512x512 size images that can be stored on a 700 MB CD with 8 bits per pixel?

To determine the approximate maximum number of 512x512 size images that can be stored on a 700 MB CD with 8 bits per pixel, calculations need to be performed based on the image size and the total storage capacity.

First, calculate the size of a single image. A 512x512 image has 262,144 pixels (512 x 512 = 262,144). Since each pixel requires 8 bits, the total size of one image in bits is:

262,144 pixels * 8 bits/pixel = 2,097,152 bits.

Converting bits to bytes, since there are 8 bits in a byte:

2,097,152 bits ÷ 8 = 262,144 bytes per image.

Next, to convert the capacity of the CD from megabytes to bytes, note that 1 MB is equal to 1,024 KB and 1 KB is equal to 1,024 bytes, so:

700 MB = 700 * 1,024 KB * 1,024 bytes = 734,003,200 bytes.

Now, to find the maximum number of images that can fit on the CD, divide the total storage capacity by the size of a single image:

734